Mekanika Bahan

5. Mekanika Bahan Summary Geometri Propertis Penampang Tunggal

Saturday, December 25, 2021

Hai hai Engineer, Berikut ini Summary Geometri Penampang Tunggal, sbb:

1. Penamapang Persegi

$A=b.h$

$\tilde{x}=\frac{1}{2}b$

$\tilde{y}=\frac{1}{2}h$

$I_{x}=\frac{bh^{3}}{12}$

$I_{y}=\frac{hb^{3}}{12}$

2. Penampang Segitiga

$A=\frac{1}{2}bh$

$\bar{x}=\frac{b}{3}$

$\bar{y}=\frac{h}{3}$

$I_{x}=\frac{1}{36}bh^{3}$

$I_{y}=\frac{1}{36}hb^{3}$

3. Penampang Lingkaran

$A=\pi r^{2}$

$I_{x}=\frac{\pi d^{4}}{64}$

$I_{y}=\frac{\pi d^{4}}{64}$

4. Penampang Setengah Lingkaran (Semi Circle)

$A=\frac{\pi r^{2}}{2}$

$\bar{x}=0$

$\bar{y}=\frac{4r}{3\pi }$

$I_{x}=\frac{\left ( 9\pi^{2}-64 \right )r^{4}}{72\pi }$

$I_{y}=\frac{\pi d^{4}}{8}$

5. Penampang Seperempat Lingkaran (Quarter Circle)

$A=\frac{\pi r^{2}}{2}$

$\bar{x}=\frac{4r}{3\pi }$

$\bar{y}=\frac{4r}{3\pi }$

$I_{x}=\frac{\left ( 9\pi^{2}-64 \right )r^{4}}{144\pi }$

$I_{y}=\frac{\left ( 9\pi^{2}-64 \right )r^{4}}{144\pi }$